Kinh nghi\u1ec7m \u0111\u00e1nh b\u1ea1ch th\u1ee7 l\u00f4 chu\u1ea9n x\u00e1c hi\u1ec7u qu\u1ea3<\/h2>\n
\u0110\u00e2y l\u00e0 t\u1eeb nh\u1eefng cao nh\u00e2n ch\u01a1i l\u00f4 \u0111\u1ec1 l\u00e2u n\u0103m chuy\u1ec1n l\u1ea1i, ta ch\u1ec9 b\u1eaft t\u1ed1i \u0111a 3 cho 1 ng\u00e0y v\u00e0 kh\u00f4ng h\u01a1n. B\u1edfi v\u00ec khi \u0111\u00e1nh 3 l\u00f4, n\u1ebfu tr\u00fang c\u1ea3 3 l\u00f4 th\u00ec th\u1eafng \u0111\u1eadm, tr\u00fang 2 l\u00f4 v\u1eabn c\u00f2n th\u1eafng, tr\u00fang 1 l\u00f4 v\u1eabn th\u1eafng nh\u01b0ng \u0111\u01b0\u1ee3c \u00edt. V\u00e0 n\u1ebfu thua c\u1ea3 3 l\u00f4 th\u00ec c\u0169ng coi nh\u01b0 m\u1ea5t, ng\u00e0y sau g\u1ee1 l\u1ea1i s\u1ed1 v\u1ed1n tr\u00ean d\u1ec5 r\u00e0ng h\u01a1n l\u00e0 b\u1ea1n ch\u01a1i c\u1ea3 ch\u1ee5c con m\u00e0 tr\u1ea3 tr\u00fang con n\u00e0o. \u0110\u00e2m ra lo\u1ea1n s\u1ed1.<\/p>\n
B\u1eaft l\u00f4 ch\u1ea1m 2 nh\u00e1y<\/h3>\n
C\u00e1ch b\u1eaft n\u00e0y l\u00e0 khi b\u1ea1n \u0111\u1ec3 \u00fd c\u00f3 con l\u00f4 n\u00e0o v\u1ec1 2 nh\u00e1y trong m\u1ed9t ng\u00e0y, h\u00f4m sau m\u00ecnh \u0111\u00e1nh ch\u1eb7n \u0111\u1ea7u \u0111u\u00f4i c\u1ee7a s\u1ed1 \u0111\u00f3.<\/p>\n
V\u00ed d\u1ee5 : Ng\u00e0y 30\/4 c\u00f3 l\u00f4 78 v\u1ec1 hai nh\u00e1y, h\u00f4m sau ta \u0111\u00e1nh ch\u1eb7n c\u1eb7p l\u00f4 77 \u2013 79, v\u00e0 th\u1ef1c t\u1ebf l\u00e0 h\u00f4m sau 1\/5 v\u1ec1 l\u00f4 79.<\/p>\n
B\u1eaft l\u00f4 r\u01a1i li\u00ean t\u1ee5c 3 ng\u00e0y<\/h3>\n
Th\u01b0\u1eddng th\u00ec l\u00f4 r\u01a1i 2 ng\u00e0y s\u1ebd v\u1ec1 th\u00eam 1 ng\u00e0y n\u1eefa. Th\u1ed1ng k\u00ea th\u1ea5y l\u00f4 r\u01a1i ra 2 ng\u00e0y th\u00ec n\u00ean \u0111\u00e1nh th\u00eam m\u1ed9t ng\u00e0y n\u1eefa v\u00e0 l\u00f3t th\u00eam con l\u1ed9n l\u1ea1i.<\/p>\n
V\u00ed d\u1ee5 : ng\u00e0y 4\/3 c\u00f3 con l\u00f4 69 ra \u0111\u00e3 2 ng\u00e0y li\u00ean ti\u1ebfp<\/p>\n
ng\u00e0y h\u00f4m sau 5\/3 ti\u1ebfp t\u1ee5c \u0111\u00e1nh 69 v\u00e0 gi\u1ea3i 3 \u0111\u00e3 v\u1ec1 04569 => tr\u00fang<\/p>\n
B\u1eaft l\u00f4 theo c\u1ea7u \u0111\u1eb9p<\/h3>\n
V\u00e0o trang ki\u1ec3m tra xem h\u00f4m nay l\u00f4 m\u00ecnh k\u1ebft c\u00f3 c\u1ea7u \u0111\u1eb9p kh\u00f4ng. N\u1ebfu c\u00f3 c\u1ea7u th\u00ec \u0111\u00e1nh l\u00f4 \u0111\u00f3 v\u00e0 nh\u1edb \u0111\u00e1nh l\u00f4 l\u1ed9n n\u1eefa.<\/p>\n
V\u00ed d\u1ee5 : ng\u00e0y 12\/4 m\u00ecnh k\u1ebft con 06, v\u00e0o trang ki\u1ec3m tra th\u1ea5y c\u00f3 c\u1ea7u \u0111\u1eb9p cho l\u00f4 06. \u0110\u00e1nh l\u00f4 06 v\u00e0 60 lu\u00f4n. K\u1ebft qu\u1ea3 chi\u1ec1u h\u00f4m \u0111\u00f3 v\u1ec1 l\u00f4 06 hai nh\u00e1y, l\u00f4 60 m\u1ed9t nh\u00e1y.<\/p>\n
<\/p>\n
B\u1eaft l\u00f4 nu\u00f4i \u0111\u1ea7u 0 \u0111\u00edt 0<\/h3>\n
Ph\u1ea3i theo d\u00f5i k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1 trong m\u1ed9t tu\u1ea7n c\u1ee7a gi\u1ea3i \u0111\u1eb7c bi\u1ec7t. Khi b\u1ea1n theo d\u00f5i th\u1ea5y xu\u1ea5t hi\u1ec7n trong 1 tu\u1ea7n c\u1ee7a gi\u1ea3i n\u00e0y th\u1ea5y s\u1ed1 0 xu\u1ea5t hi\u1ec7n \u1edf ch\u00ednh gi\u1eefa 5 s\u1ed1 gi\u1ea3i \u0111\u1eb7c bi\u1ec7t th\u00ec \u0111\u00f3 l\u00e0 d\u1ea5u hi\u1ec7u \u0111\u1ea7u \u0111u\u00f4i s\u1eafp ra l\u00f4 nh\u00e9.<\/p>\n
V\u00ed d\u1ee5 nh\u01b0 sau: K\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1 mi\u1ec1n B\u1eafc ng\u00e0y 23\/5 v\u1ec1: 25034 c\u00f3 0 n\u1eb1m ch\u00ednh gi\u1eefa n\u00ean b\u1ea1n h\u00e3y nu\u00f4i \u0111\u1ea7u\u200a\u2014\u200a\u0111u\u00f4i 0 nh\u00e9. Ng\u00e0y 25\/5 l\u00f4 v\u1ec1: 06 \u2013 04 \u2013 70 \u2013 20 \u2013 80<\/p>\n
B\u1eaft t\u1ed5ng \u0111\u1ec1<\/h3>\n
C\u00e1ch \u0111\u00e1nh l\u00f4 \u0111\u1ec1 n\u00e0y b\u1ea1n s\u1ebd ph\u1ea3i l\u1ea5y 5 s\u1ed1 c\u1ee7a gi\u1ea3i \u0111\u1eb7c bi\u1ec7t v\u00e0 c\u1ed9ng t\u1ed5ng c\u1ee7a t\u1eebng s\u1ed1 ri\u00eang bi\u1ec7t \u0111\u1ec3 \u0111\u00e1nh. N\u00ean \u0111\u00e1nh t\u1ed5ng v\u00e0 \u0111\u1ec3 cho ch\u1eafc \u0103n n\u00ean \u0111\u00e1nh th\u00eam con \u0111\u1ea3o ng\u01b0\u1ee3c. C\u00e1ch soi c\u1ea7u \u0111\u1ec1 n\u00e0y th\u01b0\u1eddng s\u1ebd cho k\u1ebft qu\u1ea3 l\u00f4 ch\u00ednh x\u00e1c nh\u1ea5t.<\/p>\n
V\u00ed d\u1ee5: K\u1ebft qu\u1ea3 xsmb ng\u00e0y 23\/3 l\u00e0 04302 -> 0+4+3+0+2 = 0, \u0111\u00e1nh 07 \u2013 70 cho 3 ng\u00e0y li\u00ean ti\u1ebfp. K\u1ebft qu\u1ea3 ng\u00e0y 26\/3 ra l\u00f4 07<\/p>\n
L\u01b0u \u00fd: Th\u01b0\u1eddng x\u1ed5 l\u00f4 t\u1eeb 2\u20135 ng\u00e0y. N\u00ean nu\u00f4i l\u00f4 trong 5 ng\u00e0y v\u00e0 n\u1ebfu qu\u00e1 5 ng\u00e0y n\u00ean b\u1ecf kh\u00f4ng nu\u00f4i.<\/p>\n
Ngh\u1ec9 gi\u1ea3i \u0111en<\/h3>\n
L\u00f4 \u0111\u1ec1 l\u00e0 tr\u00f2 ch\u01a1i gi\u1ea3i tr\u00ed mang t\u00ednh ch\u1ea5t \u0111\u1ecf \u0111en. N\u1ebfu \u0111\u1ecf th\u00ec b\u1eaft \u0111\u00e2u tr\u00fang \u0111\u00f3, nh\u01b0ng n\u1ebfu \u0111en th\u00ec ch\u1ecbu, c\u00e0ng \u0111\u00e1nh c\u00e0ng thua. Th\u1ea5y li\u00ean ti\u1ebfp 5 ng\u00e0y \u0111\u00e1nh m\u00e0 b\u1ecb thua th\u00ec n\u00ean ngh\u1ec9 x\u1ea3 \u0111en \u0111\u1ec3 \u0111\u1ea9y h\u1ebft c\u00e1i \u0111en \u0111i r\u1ed3i m\u1edbi l\u1ea1i ti\u1ebfp t\u1ee5c ch\u01a1i. Tr\u00ean \u0111\u00e2y m\u00ecnh chia s\u1ebb th\u00eam nh\u1eefng kinh nghi\u1ec7m l\u00f4 \u0111\u1ec1 qu\u00fd b\u00e1u cho c\u00e1c b\u1ea1n tham kh\u1ea3o v\u00e0 c\u00f3 h\u01b0\u1edbng \u0111i gi\u00eang c\u1ee7a m\u00ecnh. Ch\u00fac c\u00e1c b\u1ea1n \u0111\u00e1nh l\u00f4 th\u1eafng l\u00f4 \u0111\u00e1nh \u0111\u1ec1 th\u1eafng \u0111\u1ec1.<\/p>\n<\/div>\n<\/article>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n
<\/main><\/p>\n